Photon Treatment

5


PHOTON TREATMENT


MATTHEW C. WARD AND SALIM BALIK


5.1   BEAM QUALITY


5.2   FACTORS AFFECTING PHOTON DOSE DEPOSITION


5.3   MONITOR UNIT CALCULATIONS





Question 2


Explain the concept of “beam hardening.” After a beam passes through a filter, how do the maximum energy, average energy, half-value layer (HVL), and dose rate change?


 



Question 3


Explain the relationship of tube voltage, tube current, and filament current to the relative output of a kV diagnostic X-ray tube.


 




Answer 2


Beam hardening occurs when the beam passes through any matter, which acts as a filter, absorbing low-energy photons. The transmitted beam will have an increased average energy, decreased dose rate while the maximum energy is unchanged. For a diagnostic beam, this increase in energy results in an increase in HVL. In the figure, the black spectrum is the initial beam and the gray is the filtered beam.


image


 



Answer 3


The output in a kV X-ray tube is proportional to the tube current, the square of the tube voltage, and exponentially with the filament current.


 




Question 5


How many half-value layers (HVLs) of the Cerrobend are necessary to limit the transmission to 10% and 1%?


 



Question 6


How does a physical wedge affect beam quality?


 



Question 7


Does a virtual wedge affect the beam quality?


 




Answer 5


3.322 HVLs are necessary to limit the dose to 10% transmission. 6.644 HVLs are necessary for 1% transmission. As you can see, 3.3222 image is a useful number to remember to quickly calculate exponential decay as applied to either radioactive decay or transmission through HVLs.


 



Answer 6


A physical wedge, comprised of a triangle-shaped metal material that generates a gradient of beam intensities at depth. This differentially filters the low-energy X-rays, leading to beam hardening. The degree of beam hardening is more pronounced near the thicker “heel” of the wedge. A physical wedge is also responsible for increased scatter.


 



Answer 7


A virtual wedge does not produce variable beam hardening as the gradient profile is created by slowly opening one collimator jaw of the linear accelerator, rather than transmission through a physical wedge. Any scatter from the jaw is reduced by shielding in the head of the machine and does not contribute significantly to the dose experienced by the patient.


 




Question 9


What is a Thoraeus filter?


 



Question 10


Why is the order of layers in the Thoraeus filter important?


 



Question 11


What are bremsstrahlung interactions and why do they happen?


 




Answer 9


A Thoraeus filter is commonly used with diagnostic X-ray tubes. The filter consists of tin, copper, and aluminum layers to remove low-energy photons and characteristic X-rays from the beam. These low-energy photons do not contribute to image quality but increase patient dose.


 



Answer 10


The order of filter layers is important because tin contributes the most to filtration of the characteristic X-rays of the tungsten target, which fall between 58 and 69 keV. Tin’s characteristic X-rays are of very low energy and can be filtered with copper. Copper’s characteristic X-rays are filtered by a thin film of aluminum, leading to a hard beam capable of producing sharp images.


 



Answer 11


Bremsstrahlung interactions occur when a high-energy electron pass near the nucleus of an atom. The electron is deflected by the nucleus due to its Coulomb force. The electron undergoes sudden acceleration in a different direction, losing all or part of its energy in the process, which is converted into a photon. A single electron may undergo multiple bremsstrahlung interactions before finally coming to rest.


 




Question 13


Describe the source of and difference between inherent and added filtration.


 



Question 14


How is beam penumbra defined?


 



Question 15


What are the three main sources of beam penumbra in therapy photon beams?


 




Answer 13


Inherent filtration in a linear accelerator is typically caused by the tungsten target itself—as electrons interact with the target, a spectrum of photons are created via bremsstrahlung interactions. The low-energy photons may interact and be absorbed by the remaining tungsten before emerging as a part of the spectrum. This effect increases as the thickness of the target increases. Added filtration is intentionally placed in the path of a beam with the goal of increasing the average beam energy (beam hardening) or decreasing the intensity of a beam.


 



Answer 14


Beam penumbra (umbra is Latin for “shadow”) is the gradual reduction of beam intensity at the edge of a photon field. It is typically measured as the width between the 80% and 20% isodose lines, although 90% to 10% isodose lines are also used.


 



Answer 15


The three main sources of beam penumbra are transmission penumbra, geometric penumbra, and internal penumbra. Transmission penumbra occurs as the beam passes through the edge of the jaw, block, or multileaf collimator (MLC). Geometric penumbra occurs because the source is not a point-source. Internal penumbra is due to scatter within the patient.


 




Question 17


How is the beam energy changed by the flattening filter?


 



Question 18


How is the beam flatness specified?


 




Answer 17


X-ray intensity is forward peaked after the target before the flattening filter. The flattening filter is thicker in the middle and tapers off toward the edges so that the central region is attenuated more than the periphery to make the beam flat. As a result, the beam will be hardened more in the center than the periphery (lower average energy in the periphery). This results in a beam that is peaked at depths greater than 10 cm. The flattening filter also reduces the dose rate significantly.


 



Answer 18


Beam flatness is specified at 10 cm depth and within the area bounded by 80% of the field size or 1 cm inside the field edge. The beam flatness should be within +–3% of the central axis dose at 10 cm depth.


 




Question 20


Parallel opposed beams are frequently used in radiation therapy. They provide uniform dose distribution for the target with a simple and reproducible setup. One disadvantage of this technique is called “tissue lateral effect.” How does this effect change with energy and patient thickness?


 



Question 21


How is “integral dose” defined and how does it change with energy?


 




Answer 20


The midpoint between the opposed beams is the prescription point. The maximum dose to the midpoint dose (prescription point) ratio increases with patient thickness and decreases with energy. As a result, it is better to use higher energy X-ray beams (>10 MV) for large patients (>20 cm) to improve homogeneity of the dose distribution and preserve subcutaneous tissue.


 



Answer 21


Integral dose is simply mass × dose if dose is uniform throughout the region, or the sum of the energy deposited. If dose volume histogram is calculated, the integral dose is the area under the contour of the external, which includes all tissue of the patient. The unit of “integral dose” is kg/Gy or joule. It is used in determining treatment plan quality in regards to how much dose is delivered outside the target. The integral dose decreases with energy.


 




Question 23


Define the term “effective energy” for a heterogeneous X-ray beam.


 



Question 24


What term is used to specify the quality of a megavoltage X-ray beam?


 



Question 25


Why are electron energies written as megaelectron volts (MeVs) but photon energies as megavolts (MVs)?


 




Answer 23


The “effective energy” is defined as the energy of a monoenergetic X-ray beam that has the same half-value layer as the heterogeneous X-ray beam.


 



Answer 24


The percent depth dose (PDD) value at 10 cm depth of a 10 cm × 10 cm field size with source to skin distance of 100 cm is used to define the beam quality.


 



Answer 25


Electron energies are monoenergetic as they leave the accelerating waveguide but photons are heterogeneous in energy. MV photon energy represents the highest energy X-ray (in MeVs) in the spectrum.




Question 2


How and why is the percent depth dose (PDD) at 10 cm affected by increases in field size, energy, source to skin distance (SSD), and physical wedges?


 



Question 3


Explain the shape of a megavoltage central-axis percent depth dose (PDD) curve. Graph the PDD curve of a 6 MV beam. Label the curve at 0, 1.5, and 10 cm depth. Label the approximate slope of the beam between 1.5 and 10 cm?


 




Answer 2























PDD Why?
Field size Increases Increased scatter
Energy Increases Increased penetration due to increased energy
SSD Increases Inverse square law (Mayneord factor)
Physical wedge Increases Beam hardening

 



Answer 3


The PDD curve reports dose deposition as a function of depth for a radiation beam. The PDD on the surface for megavoltage energies is below 100% as the incident photons produce high-energy electrons which travel a distance before coming to rest and depositing energy. This effect explains the “skin sparing” properties of megavoltage therapy. The peak in the curve known as Dmax, occurs deeper. The curve then declines, or attenuates, due to a combination of the inverse-square law, absorption, and scatter.


image


 




Question 5


What is the percent change in the percent depth dose (PDD) per centimeter for cobalt-60 (Co-60), 6 and 10 MV photons under standard conditions?


 



Question 6


While you are on-call over the weekend you wish to treat a 20 cm long by 8 cm wide posterior to anterior (PA) spine field. Calculate the equivalent square necessary to complete the hand calculation. Why is the equivalent square necessary?


 




Answer 5


Co-60 attenuates at approximately 4% per cm, 6 MV beams attenuate at approximately 3.5% per cm, and 10 MV attenuates at approximately 3.3% per cm. Note that these numbers are approximation, as the values change with depth.


 



Answer 6


image


where S is side of equivalent square, A and P are, respectively, the area and perimeter of the rectangular field.


image


The square field with 11.4 cm side is equivalent to a 20 cm × 8 cm rectangular field. Usually percent depth dose (PDD) or tissue maximum ratio (TMR) values are only tabulated for square fields. A rectangular field will have approximately the same PDD or TMR as its equivalent square field. There are also other more complex methods to approximate the PDD or TMR for irregular field shapes like Clarkson’s method.


 

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Apr 9, 2017 | Posted by in ONCOLOGY | Comments Off on Photon Treatment

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